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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Understanding +4 | -1

{\cos ^{ - 1}}\left( {\frac{1}{2}} \right) + 2{\sin ^{ - 1}}\left( {\frac{1}{2}} \right)

is equal to

View answer and explanation

Correct option: C

\frac{{2\pi }}{3}

Option C (

\frac{{2\pi }}{3}

) is correct because

{\cos ^{ - 1}}(\frac{1}{2}) = \frac{\pi}{3}

and

{\sin ^{ - 1}}(\frac{1}{2}) = \frac{\pi}{6}

, so the expression evaluates to

\frac{\pi}{3} + 2(\frac{\pi}{6}) = \frac{{2\pi }}{3}

.

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