JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

Let

f(x)=1+\sin (3 x) \cdot g(x)

where

g(x)

is differentiable, then

f^{\prime}(0)

View answer and explanation

Correct option: B

3 g(0)

Option B (

3 g(0)

) is correct because the derivative

f'(x)

is calculated using the product rule and then evaluated at

x=0

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\frac{{dy}}{{dx}}

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