JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

(\alpha, \beta)

are the roots of equation

x^2-p x+q=0

and

\left(\alpha^{\prime}, \beta^{\prime}\right)

are that of

x^2-p^{\prime} x+q^{\prime}=0

, then

\left(\alpha-\alpha^{\prime}\right)^2+\left(\beta-\alpha^{\prime}\right)^2+\left(\alpha-\beta^{\prime}\right)^2+\left(\beta-\beta^{\prime}\right)^2=

View answer and explanation

Correct option: A

2\left(p^2-2 q+p^{\prime 2}-2 q^{\prime}-p p^{\prime}\right)

Option A (

2\left(p^2-2 q+p^{\prime 2}-2 q^{\prime}-p p^{\prime}\right)

) is correct because it is obtained by expanding the given expression and using Vieta's formulas to simplify.

More Questions from QUADRATIC EQUATIONS

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

\;a \ne 0,

9{x^2} - 18\left| x \right| + 5 = 0

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