If $y = {a^x}.{b^{2x - 1}},$ then $\frac{{{d^2}y}}{{d{x^2}}}$ is

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y = {a^x}.{b^{2x - 1}},

then

\frac{{{d^2}y}}{{d{x^2}}}

View answer and explanation

Correct option: D

y{(\log a{b^2})^2}

Option D (

y{(\log a{b^2})^2}

) is correct because it is the result of taking the second derivative of the given function using logarithmic differentiation.

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