If $f(2)=4$ and $f^{\prime}(2)=1$, then $\mathop {\lim }\limits_{x \to 2} \frac{{x\,f(2) - 2f(x)}}{{x - 2}} = $

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f(2)=4

and

f^{\prime}(2)=1

, then

\lim\limits_{x \to 2} \frac{{x\,f(2) - 2f(x)}}{{x - 2}} =

View answer and explanation

Correct option: A

Option A (2) is correct because it is the result of evaluating the limit using the definition of the derivative and the given values.

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