JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f(1)=3, f^{\prime}(1)=-\frac{1}{3}

, then the derivative of

\left|x^{11}+f(x)\right|^{-2}

x=1

, is

View answer and explanation

Correct option: D

f^{\prime}(1)

Option D (

f^{\prime}(1)

) is correct because after applying the chain rule and substituting the given values, the derivative simplifies to

f^{\prime}(1)

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f(x)=|x|^{|\tan x|}

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x

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x y=1

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x=k, k

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y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

\frac{d}{d x} \sin ^{-1}\left(3 x-4 x^{3}\right)

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v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}