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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1
Let f(x)f\left( x \right) be a quadratic polynomial such that f(−2)+f(3)=0.f\left( { - 2} \right) + f\left( 3 \right) = 0. If one of the roots of f(x)=0f\left( x \right) = 0 is –1, then the sum of the roots of f(x)=0f\left( x \right) = 0 is equal to:
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Correct option: A
113\frac{{11}}{3}
Option A (113\frac{{11}}{3}) is correct because it is the sum of the roots of the quadratic equation, derived using the given condition f(−2)+f(3)=0f(-2) + f(3) = 0 and the fact that one root is -1.

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