An emf of $0.5 \mathrm{~V}$ is developed in the secondary coil, when current in primary coil changes from $5.0 \mathrm{~A}$ to $2.0 \mathrm{~A}$ in 300 millisecond. Calculate the mutual inductance of the two coils.

JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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An emf of

0.5 \mathrm{~V}

is developed in the secondary coil, when current in primary coil changes from

5.0 \mathrm{~A}

2.0 \mathrm{~A}

in 300 millisecond. Calculate the mutual inductance of the two coils.

View answer and explanation

Correct option: A

0.05 \mathrm{~H}

Option A (0.05 H) is correct because it is calculated using the formula for induced emf in terms of mutual inductance.

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R

n

i=i_0 \sin \omega t

N

4 \mathrm{sec}

0.1\,\,{m^2}

\mathrm{60}

\mathrm{0}\mathrm{.4}\,\,\mathrm{T}

\mathrm{100}

\mathrm{50}\,\,\mathrm{mH}

\mathrm{2 A}