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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A solid sphere of mass 2 kg2 \mathrm{~kg} is rolling on a frictionless horizontal surface with velocity 6 m/s\mathrm{m} / \mathrm{s}. It collides on the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring =36 N/m=36 \mathrm{~N} / \mathrm{m}).
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Correct option: B
2.8 m\sqrt{2.8} \mathrm{~m}
Option B (2.8 m\sqrt{2.8} \mathrm{~m}) is correct because it's the maximum compression calculated by equating the kinetic energy of the rolling sphere to the potential energy stored in the spring.

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