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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
If x=a(cosθ+θsinθ)x = a\left( {\mathrm{cos\theta } + \mathrm{\theta sin\theta }} \right) and y=a(sinθ−θcos⁡θ),y = a(\mathrm{sin\theta } - \theta \cos \theta ), then dydx\frac{{dy}}{{dx}} is equal to
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Correct option: B
tan θ\mathrm{tan}\,\theta
Option B (tan θ\mathrm{tan}\,\theta) is correct because it is the result of dividing dydθ\frac{dy}{d\theta} by dxdθ\frac{dx}{d\theta}.

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