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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Application +4 | -1
If y=asin⁡3θy = a{\sin ^3}\theta and x=acos⁡3θ,x = a{\cos ^3}\theta , then at θ=π3,dydx\theta = \frac{\pi }{3},\frac{{dy}}{{dx}} is equal to
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Correct option: B
−3- \sqrt 3
Option B ( −3\ - \sqrt 3) is correct because, after finding dydx\frac{{dy}}{{dx}} and substituting θ=π3\theta = \frac{\pi }{3}, the result is −3-\sqrt{3}.

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