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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy
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Application +4 | -1
cos⁡{cos⁡−1(−17)+sin⁡−1(−17)}  =\cos \left\{ {{{\cos }^{ - 1}}\left( { - \frac{1}{7}} \right) + {{\sin }^{ - 1}}\left( { - \frac{1}{7}} \right)} \right\}\; =
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Correct option: B
00
Option B (0) is correct because cos⁡−1(−17)+sin⁡−1(−17)=π2{\cos ^{ - 1}}( - \frac{1}{7}) + {\sin ^{ - 1}}( - \frac{1}{7}) = \frac{\pi}{2}, and cos⁡(π2)=0\cos(\frac{\pi}{2}) = 0.

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