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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
Two spherical bodies of the same mass M are moving with velocities v1 and v2{v_1}\,and\,{v_2} .These collide perfectly inelastically , then the loss in kinetic energy is
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Correct option: C
14M(v1−v2)2\frac{1}{4}M{\left( {{v_1} - {v_2}} \right)^2}
Option C (14M(v1−v2)2\frac{1}{4}M{\left( {{v_1} - {v_2}} \right)^2}) is correct because it represents the kinetic energy lost during a perfectly inelastic collision of two equal masses.

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