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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1
The real values of aa for which the quadratic equation 3x2+2(a2+1)x+(a2−3a+2)=03 x^2+2\left(a^2+1\right) x+\left(a^2-3 a+2\right)=0 possesses roots of opposite signs lie in
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Correct option: C
(1,2)(1,2)
Option C ((1,2)) is correct because the product of roots must be negative, leading to the interval (1,2).

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