JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

\cos ^{-1} x+\cos ^{-1} y+\cos ^{-1} z=\pi

, where

-1 \leq x, y \leq 1

and

x+y \geq 0

, then

x^2+y^2+z^2+2 x y z

is equal to

View answer and explanation

Correct option: B

Option B, 1, is correct because by using the cosine addition formula and simplifying, we can derive that

x^2 + y^2 + z^2 + 2xyz = 1

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