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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A body of mass 2 kg2 \mathrm{~kg} moving under a force has relation between displacement xx and time tt as x=t33x=\frac{t^3}{3} where xx is in metre and tt is in sec. The work done by the body in first two second will be
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Correct option: B
16 joule
Option B (16 joule) is correct because the work done is equal to the change in kinetic energy, which is calculated using the velocity at t=2s.

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