If $x=\frac{t+1}{t}, y=\frac{t-1}{t}$ then $\frac{d^2 y}{d x^2}$ at $t=1$

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

x=\frac{t+1}{t}, y=\frac{t-1}{t}

then

\frac{d^2 y}{d x^2}

t=1

View answer and explanation

Correct option: A

Option A (0) is correct because the second derivative is zero, as the first derivative is a constant.

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