JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

\sqrt {1 - {x^2}} + \sqrt {1 - {y^2}} = a\left( {x - y} \right)

, then

\frac{{dy}}{{dx}}

equals

View answer and explanation

Correct option: B

\sqrt {\frac{{1 - {y^2}}}{{1 - {x^2}}}}

Option B (

\sqrt {\frac{{1 - {y^2}}}{{1 - {x^2}}}}

) is correct because after substituting

x = \sin A

and

y = \sin B

, and differentiating implicitly, the expression simplifies to this result.

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