Skip to main content
Back to WORK-ENERGY-POWER

JEE PHYSICS MCQ: WORK-ENERGY-POWER

1 Medium
1 of 1
Application +4 | -1
A force moves a block of mass 4 kg4 \mathrm{~kg} on horizontal smooth surface such that the position xx of the block as a function of time tt is given as x=t3x=t^3. Here xx is in metre and tt is in second. Work done by the force in first three second is
View answer and explanation
Correct option: D
1458 J1458 \mathrm{~J}
Option D (1458 J1458 \mathrm{~J}) is correct because the work done is equal to the change in kinetic energy, and the velocity is the derivative of the position function.

More Questions from WORK-ENERGY-POWER

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.