JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f(x)=x+\tan x

and

f

is inverse of

g

, then

g^{\prime}(x)

is equal to

View answer and explanation

Correct option: C

\frac{1}{2+[g(x)-x]^2}

Option C is correct because it uses the inverse function derivative formula and correctly substitutes the given function.

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x

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y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

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v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}