If $x=\phi(t), y=\psi(t)$, then $\frac{d^2 y}{d x^2}$ is equal to

$\frac{\phi^{\prime \prime}}{\psi^{\prime \prime}}$

$\frac{\psi^{\prime \prime}}{\phi^{\prime \prime}}$

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

x=\phi(t), y=\psi(t)

, then

\frac{d^2 y}{d x^2}

is equal to

View answer and explanation

Correct option: B

\frac{\phi^{\prime} \psi^{\prime \prime}-\psi^{\prime} \phi^{\prime \prime}}{\left(\phi^{\prime}\right)^3}

Option B is correct because it is the result of applying the chain rule and quotient rule to find the second derivative of a parametric function.

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