JEE PHYSICS MCQ: ATOMS

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Analyzing +4 | -1

Statement I: The ionisation potential of hydrogen is found to be

13.6 \mathrm{~eV}

, the ionisation potential of doubly ionised lithium is

122.4 \mathrm{~eV}

.
Statement II: Energy in the

n

th state of hydrogen atom is

E_n=-\frac{13.6}{n^2}

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Correct option: B

Statement I is true; Statement II is true; Statement II is not the correct explanation for Statement I

Option B is correct. Statement I is true based on Bohr's theory, and Statement II correctly states the energy levels of hydrogen, but Statement II is not the direct explanation for the specific values in Statement I.

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The de-Broglie wavelength of an electron in the first Bohr orbit is The volume occupied by an atom is greater than the volume of the nucleus by a factor of about For a hydrogen atom, when electron jump from

n

=2

{n}=1

, then wave length of radiation emitted found to be

\lambda_0

. Then, for which transition of electron of a 'He' atom, the wavelength of radiation emitted will be equal to '

\lambda_0

'. Energy of characteristic X-ray is a consequence of Taking Rydberg’s constant

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m

, first and second wavelength of Balmer series in hydrogen spectrum is When hydrogen atom is in its first excited level, its radius is its ground state radius