JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

(\sin y)^{\sin (\pi x / 2)}-\frac{\sqrt{3}}{2} \operatorname{Sec}^{-1}(2 x)+2^x \tan (\log (x+2))=0

then

d y / d x

x=-1

View answer and explanation

Correct option: C

\frac{3}{\pi \sqrt{\pi^2-3}}

Option C (

\frac{{3}}{{\pi \sqrt{{\pi^2-3}}}}

) is correct because by differentiating the given equation implicitly and substituting x = -1 and solving for dy/dx, we obtain this result.

More Questions from DIFFERENTIATION

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f(x)=|x|^{|\tan x|}

f^{\prime}\left(\frac{-\pi}{6}\right)

x

y

x>0

x y=1

x+y

f(x)=[x] \sin (\pi x)

[x]

x

x=k, k

f(x)

y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

\frac{d}{d x} \sin ^{-1}\left(3 x-4 x^{3}\right)

z = y + f\left( v \right),

v = \left( {\frac{x}{y}} \right),

v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}