JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Medium

1 of 1

Application +4 | -1

Let

f\left( x \right) = {x^3}

use Mean value theorem to write

\frac{{f\left( {x + h} \right) - f\left( x \right)}}{h} = f'\left( {x + \theta h} \right)

with

0 < \theta < 1

. If

x \ne 0

, then

\lim\limits_{h \to 0} \theta

is equal to

View answer and explanation

Correct option: C

0.5

Option B (

2:1

) is correct because the ratio of the subtangent to the abscissa for the given parabola is 2:1.

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