JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

y^2=P(x)

is a polynomial of degree 3 , then

2 \frac{d}{d x}\left(y^3 \frac{d^2 y}{d x^2}\right)=

View answer and explanation

Correct option: C

P(x) P^{\prime \prime \prime}(x)

Option C is correct because by differentiating

y^2 = P(x)

twice and substituting, the expression

2 \frac{d}{dx}\left(y^3 \frac{d^2 y}{dx^2}\right)

simplifies to

P(x) P^{\prime \prime \prime}(x)

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