If $y = {2^{\log x}}$, then $\frac{{dy}}{{dx}}$ is

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y = {2^{\log x}}

, then

\frac{{dy}}{{dx}}

View answer and explanation

Correct option: D

\frac{{{2^{\log x}}.\log 2}}{x}

Option D (

\frac{{{2^{\log x}}.\log 2}}{x}

) is correct because it is the result of applying the chain rule and the derivative of exponential functions.

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