JEE PHYSICS MCQ: ATOMS

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For principal quantum number

n = 3

, the possible values of orbital quantum number

'l'

are

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Correct option: C

\mathrm{0, 1, 2}

Option C (

\mathrm{0, 1, 2}

) is correct because for

n=3

, the possible values of

l

are 0 to

n-1

, which are 0, 1, and 2.

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The de-Broglie wavelength of an electron in the first Bohr orbit is The volume occupied by an atom is greater than the volume of the nucleus by a factor of about For a hydrogen atom, when electron jump from

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\lambda_0

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