JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f^{\prime}(x)=\frac{\cos (\log x)}{x}, f^{\prime}(1)-0

and

y=f\left(\frac{2 x+3}{3-2 x}\right)

, then

\frac{d y}{d x}=\ldots \ldots

View answer and explanation

Correct option: C

\frac{12}{(3-2 x)^2} \sin \left(\log \left(\frac{2 x+3}{3-2 x}\right)\right)

Option C is correct because it involves finding the derivative using the chain rule and the given derivative of f(x).

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