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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
Let f(x)=sin⁡x,g(x)=x2f(x) = \sin x,\mathrm{g}\left( x \right) = {x^2} and  h(x)=log⁡ex\,h\left( x \right) = {\log _e}x. If F(x)=(hog  of)(x)F\left( x \right) = \left( {hog\,\,of} \right)\left( x \right), then F′′(x)F''\left( x \right) is equal to
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Correct option: D
−2cosec2x- 2\mathrm{cose}{\mathrm{c}^2}x
Option D (−2cosec2x- 2\mathrm{cose}{\mathrm{c}^2}x) is correct because after finding F(x) and differentiating twice, the result is −2cosec2x- 2\mathrm{cose}{\mathrm{c}^2}x.

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