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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A particle of mass MM is moving in a circle of fixed radius RR in such a way that its centripetal acceleration at time tt is given by n2Rt2n^2 R t^2 where nn is a constant. The power delivered to the particle by the force acting on it, is
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Correct option: B
Mn2R2tM n^2 R^2 t
Option B (Mn2R2tM n^2 R^2 t) is correct because the power delivered is the product of the tangential force and the tangential velocity, which results in Mn2R2tM n^2 R^2 t.

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