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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
If y=sec⁡(tan⁡−1x)y=\sec \left(\tan ^{-1} x\right), then dydx\frac{d y}{d x} at x=1x=1 is equal to
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Correct option: D
12\frac{1}{\sqrt{2}}
The correct answer is D (12\frac{1}{\sqrt{2}}) because it is the value of the derivative of y with respect to x at x=1, after simplifying the function and differentiating.

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