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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A uniform rope of mass 1 kg1 \mathrm{~kg} and length 1 m1 \mathrm{~m} is lying on the ground. One end of the rope is pulled up by a worker with the constant velocity of 1 m/s1 \mathrm{~m} / \mathrm{s}. The average power supplied by the worker in pulling the entire rope just off the ground such that the rope becomes vertical is (take g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2 )
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Correct option: A
5.5 W5.5 \mathrm{~W}
Option A (5.5 W5.5 \mathrm{~W}) is correct because it is the average power calculated by considering both the potential energy increase and the kinetic energy of the rope as it's lifted.

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