JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

Let

K

be the set of all real values of

x

, where the function

f(x) = \sin \left| x \right| - \left| x \right| + 2(x - \pi )\cos \left| x \right|

is not differentiable. Then, the set

K

is equal to

View answer and explanation

Correct option: B

\phi

(an empty set)

Option B (

\phi

) is correct because the function

f(x)

is differentiable for all real values of

x

, meaning there are no points where it's not differentiable.

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