If $y=\left|x-x^2\right|$, then $\frac{d y}{d x}$ at $x=1$.

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Hard

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Analyzing +4 | -1

y=\left|x-x^2\right|

, then

\frac{d y}{d x}

x=1

View answer and explanation

Correct option: C

Does not exist

Option C (Does not exist) is correct because the left-hand derivative and right-hand derivative at x=1 are not equal, indicating a non-differentiable point.

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