If ${e^y} + xy = e$, then the value of $\frac{{{d^2}y}}{{d{x^2}}}$ for $x = 0$, is

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

{e^y} + xy = e

, then the value of

\frac{{{d^2}y}}{{d{x^2}}}

for

x = 0

, is

View answer and explanation

Correct option: B

\frac{1}{{{e^2}}}

Option B (

\frac{1}{{{e^2}}}

) is correct because after differentiating the given equation twice and substituting x=0 and y=1, the second derivative is found to be

\frac{1}{{{e^2}}}

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