JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

The derivative of

{\sin ^{ - 1}}\left( {\frac{{2x}}{{1 + {x^2}}}} \right)

with respect to

{\tan ^{ - 1}}\left( {\frac{{2x}}{{1 - {x^2}}}} \right)

View answer and explanation

Correct option: B

Option B (1) is correct because both

{\sin ^{ - 1}}\left( {\frac{{2x}}{{1 + {x^2}}}} \right)

and

{\tan ^{ - 1}}\left( {\frac{{2x}}{{1 - {x^2}}}} \right)

are equal to

2{\tan ^{ - 1}}x

, so their derivatives with respect to each other is 1.

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