JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1

The solution set of the inequation

\left| {\frac{{2x - 1}}{{x - 1}}} \right| > 2,

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Correct option: A

\left( {3/4\;,1} \right) \cup \left( {1,\infty } \right)

Option A

\left( {3/4\;,1} \right) \cup \left( {1,\infty } \right)

is the correct solution set obtained by solving the inequality by considering both positive and negative cases of the absolute value.

More Questions from QUADRATIC EQUATIONS

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{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

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