Skip to main content
Back to QUADRATIC EQUATIONS

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy
1 of 1
Application +4 | -1
The values of ' aa ' for which one root of the equation x2−(a+1)x+a2+a−8=0x^{2}-(a+1) x+a^{2}+a-8=0 exceeds 2 and the other is lesser than 2 , are given by :
View answer and explanation
Correct option: C
 -2
Option C (&nbsp;-2) is correct because the condition that one root exceeds 2 and the other is less than 2 implies f(2)<0f(2) < 0, which leads to the solution a<−2a < -2.

More Questions from QUADRATIC EQUATIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.