JEE PHYSICS MCQ: ATOMS

1 Medium

1 of 1

Application +4 | -1

An electron in the hydrogen atom jumps excited state

n

to the ground state. The wavelength so emitted illuminates a photosensitive material having work function

2.75\;eV.

If the stopping potential of the photoelectron is

10\;eV,

then the value of

n

View answer and explanation

Correct option: D

Option D (4) is correct because the energy difference between the excited state n and the ground state corresponds to the energy of the emitted photon, which can be calculated from the work function and stopping potential.

More Questions from ATOMS

Practice All Chapter MCQs →

The de-Broglie wavelength of an electron in the first Bohr orbit is The volume occupied by an atom is greater than the volume of the nucleus by a factor of about For a hydrogen atom, when electron jump from

n

=2

{n}=1

, then wave length of radiation emitted found to be

\lambda_0

. Then, for which transition of electron of a 'He' atom, the wavelength of radiation emitted will be equal to '

\lambda_0

'. Energy of characteristic X-ray is a consequence of Taking Rydberg’s constant

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m

, first and second wavelength of Balmer series in hydrogen spectrum is When hydrogen atom is in its first excited level, its radius is its ground state radius