JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The solution set of the equation

pq{x^2} - {\left( {p + q} \right)^2}x + {\left( {p + q} \right)^2} = 0

View answer and explanation

Correct option: D

\left\{ {\frac{{p + q}}{p},\;\frac{{p + q}}{q}} \right\}

The correct answer is D (

\left\{ {\frac{{p + q}}{p},\;\frac{{p + q}}{q}} \right\}

) because these are the solutions obtained by solving the given quadratic equation using the quadratic formula or factoring.

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\alpha ,\;\beta

{x^2} - px + q = 0

{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

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