JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

\alpha ,\beta

are the roots of the equation

a{x^2} + bx + c = 0

, then

\frac{\alpha }{{a\beta + b}} + \frac{\beta }{{a\alpha + b}}

is equal to

View answer and explanation

Correct option: D

- \frac{2}{a}

Option D (-2/a) is correct because simplifying the given expression using Vieta's formulas leads to -2/a.

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{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

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