JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y

is a function of

x

and

\log \left( {x + y} \right) = 2xy,

the value of

y'\left( 0 \right)

is equal to

View answer and explanation

Correct option: A

Option A (1) is correct because, after differentiating the given equation and substituting x=0, the value of

y'(0)

is found to be 1.

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