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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
If u=sin⁡−1(xy)+tan⁡−1(yx),u = {\sin ^{ - 1}}\left( {\frac{x}{y}} \right) + {\tan ^{ - 1}}\left( {\frac{y}{x}} \right), then the value of x∂u∂x+y∂u∂yx\frac{{\partial u}}{{\partial x}} + y\frac{{\partial u}}{{\partial y}} is
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Correct option: A
0
Option A (0) is correct because the expression is a homogeneous function of degree 0, and therefore, by Euler's theorem, x∂u∂x+y∂u∂y=0x\frac{{\partial u}}{{\partial x}} + y\frac{{\partial u}}{{\partial y}} = 0.

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