If $\tan ^{-1} \frac{\sqrt{1+x^2}-1}{x}=4^{\circ}$, then

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

\tan ^{-1} \frac{\sqrt{1+x^2}-1}{x}=4^{\circ}

, then

View answer and explanation

Correct option: D

x=\tan 8^{\circ}

Option D (

x=\tan 8^{\circ}

) is correct because substituting

x = \tan \theta

and simplifying using trigonometric identities leads to

\theta = 8^{\circ}

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