JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

Suppose

a, b \in \mathbf{R}, a \neq 0

and

2 a+b \neq 0

. A root of the equation

(a+b)(a x+b)(a-b x)=\left(a^2 x-b^2\right)(a+b x)

View answer and explanation

Correct option: D

-\frac{a+2 b}{2 a+b}

Option D (

- \frac{{a+2b}}{{2a+b}}

) is correct because by simplifying and factoring the given equation, we find that one of the roots is

- \frac{{a+2b}}{{2a+b}}

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a

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