If $y = \sin px$ and ${y_n}$ is the $nth$ derivative of $y$, then $\left| {\begin{array}{*{20}{c}} y&{{y_1}}&{{y_2}}\\ {{y_3}}&{{y_4}}&{{y_5}}\\ {{y_6}}&{{y_7}}&{{y_8}} \end{array}} \right|$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

y = \sin px

and

{y_n}

is the

nth

derivative of

y

, then

\left| {\begin{array}{cccccccccccccccccccc} y&{{y_1}}&{{y_2}}\\ {{y_3}}&{{y_4}}&{{y_5}}\\ {{y_6}}&{{y_7}}&{{y_8}} \end{array}} \right|

is equal to

View answer and explanation

Correct option: B

The correct answer is B (0) because the determinant of the matrix is zero due to identical rows after simplification.

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