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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If a=sin⁡−1(sin⁡(5))a=\sin ^{-1}(\sin (5)) and b=cos⁡−1(cos⁡(5))b=\cos ^{-1}(\cos (5)), then a2+b2a^2+b^2 is equal to
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Correct option: B
8π2−40π+508 \pi^2-40 \pi+50
Option A (8π2−40π+508 \pi^2-40 \pi+50) is correct because it is the correct simplification after finding a and b using the given conditions.

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