JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Analyzing +4 | -1

\alpha = {\sin ^{ - 1}}\frac{{\sqrt 3 }}{2} + {\sin ^{ - 1}}\frac{1}{3},\;\beta = {\cos ^{ - 1}}\frac{{\sqrt 3 }}{2} + {\cos ^{ - 1}}\frac{1}{3}

, then

View answer and explanation

Correct option: C

\alpha < \beta

Option C (

\alpha < \beta

) is correct because, given

\alpha + \beta = \pi

, and by comparing the values of

\alpha

and

\frac{\pi}{2}

, it can be shown that

\beta > \frac{\pi}{2}

, thus

\alpha < \beta

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