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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy
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Application +4 | -1
If sin⁡−1(1−x)−2sin⁡−1x=π2{\sin ^{ - 1}}\left( {1 - x} \right) - 2{\sin ^{ - 1}}x = \frac{\pi }{2}, then xx equals
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Correct option: C
0
Option C (0) is correct because, after solving the equation, x=0x = 0 is the only solution that satisfies the original equation.

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