If $x\sqrt {1 + y} + y\sqrt {1 + x} = 0$, then $\frac{{d{\rm{y}}}}{{{\rm{d}}x}}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Hard

1 of 1

Application +4 | -1

x\sqrt {1 + y} + y\sqrt {1 + x} = 0

, then

\frac{{d\mathrm{y}}}{{\mathrm{d}x}}

is equal to

View answer and explanation

Correct option: B

- \frac{1}{{{{\left( {1 + x} \right)}^2}}}

Option B (

- \frac{1}{{{{\left( {1 + x} \right)}^2}}}

) is correct because it is the derivative of the function obtained after simplifying the given equation.

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